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Jaeger-LeCoultre

Radial force on a crown

 

Lots of simplifications here, so bear with me.

I have simplified numbers so I can do them in my head and on the calculator in my mobile, so exact values are incorrect, but magnitude should be OK (and please correct me if I am wrong - I can take the embarrassment!)

If your wrist is moving through the water at around 20km/h (~5m/s)

Then the dynamic pressure is: P=0.5 x Density of water x velocity^2

So:   P=0.5 x 1000 x (5x5)

         P=12500Pa=~0.125 atm.

Radial force on crown: (I am simplifying the side surface of a crown from a curved surface to a rectangular cross-section, but this is a worst case).

So let's make the cross section largish 7mm x 5mm=35mm^2=0.35cm^2

P=F/A ->  0.125=F/0.35 -> 0.125 x 0.35=F=0.04kg OR 0.4N

Not much at all.

The ISO spec calls for a sideways nudge on the crown of 5N or the based on the above assumptions...equivalent of moving though the water at....around 60km/h...fast!

 

 

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